# What Is The Probability That A Five-Card Poker Hand Contains Exactly One Ace?

To calculate the probability of a five-card poker hand containing exactly one ace. The probability can be calculated by dividing the number of ways that the hand can be made, by the total number of possible hands. The number of ways that the hand can be made is 4 because there are 4 aces in a deck of cards. The total number of possible hands is 52 (52 cards in a deck). Therefore, the probability of a five-card poker hand containing exactly one ace is 4/52 or 1/13.

Poker is a game of chance, and as such, the probabilities of various events occurring during the game are important to know. One such probability is the likelihood of being dealt a hand containing exactly one ace. This probability can be calculated by dividing the number of ways that the hand can be made (4), by the total number of possible hands (52). This gives us a probability of 1/13 or approximately 7.69%. This means that, on average, you can expect to be dealt a hand containing exactly one ace once every 13 hands or so.

There are many other probabilities in poker that can be calculated in a similar fashion. For example, the probability of being dealt a flush (a hand containing all cards of the same suit) is approximately 0.1984%, while the probability of being dealt a royal flush (the highest possible hand in poker, containing an Ace, King, Queen, Jack and 10 all of the same suit) is a mere 0.000154%! Knowing the probabilities of various events occurring can give you an edge over other players who do not know (or care to know) them. So next time you sit down to play poker, remember to calculate the odds!